3^2y-4(3^y+1)+27=0

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Solution for 3^2y-4(3^y+1)+27=0 equation: 



3^2y-4(3^y+1)+27=0

We multiply parentheses

3^2y-12y-4+27=0

We add all the numbers together, and all the variables

-12y+3^2y+23=0

We move all terms containing y to the left, all other terms to the right

-12y+3^2y=-23

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